The first term of an AP is 25; sum of the first n terms being 60 and nth term is −17. Find the tenth
term.
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18
first term = 25
sum of first n terms = 60
Sn = 60 ,
use formula,
Sn =n/2{first term + nth term }
60 =n/2{ 25 -17}
120 = n(8)
n= 15
hence, Tn = -17
use formula,
Tn = a + (n -1)d
-17 = 25 + (15-1)d
-42 = 14d
d = -3
so, 10th term = 25 + (10-1)(-3)
= 25 -27 = -2
sum of first n terms = 60
Sn = 60 ,
use formula,
Sn =n/2{first term + nth term }
60 =n/2{ 25 -17}
120 = n(8)
n= 15
hence, Tn = -17
use formula,
Tn = a + (n -1)d
-17 = 25 + (15-1)d
-42 = 14d
d = -3
so, 10th term = 25 + (10-1)(-3)
= 25 -27 = -2
abhi178:
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Nice question.
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Answer explained below.
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