Question

the first term of an ap is 4 and common difference is-3, find its 12 term​

Answer 1

Answer:

First term ( A ) = 4

And,

Common Difference ( D ) = 3

12 th term = A + 11D

=> 4 + 11 × 3

=> 4 + 33

=> 37

First term (A1 ) of another AP = -5

Let common Difference of another AP be D1

According to question,

12 th term of an AP = 8 th term of an another ap.

37 = A1 + 7D1

37 = -5 + 7D1

7D1 = 37+5

D1 = 42/7

D1 = 6

Hence,

common Difference (D1) of another AP is 6.

Hope this helps you Buddy!!

Pls mark me as brainliest!!