Question

the first term of an ap is 4 and common difference is -3 find its 12th term
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Answer 1

Step-by-step explanation:

• a=4,d=–3,n=12
• t1=4
• tn=a+(n–1)d
• t12=4+(12–1)×-3
• t12=4+11×–3
• t12=4–33
• t12=–29

So,12th term of A.P is –29

Answer 2

Answer:

Sa=4,d=–3,n=12

t1=4

tn=a+(n–1)d

t12=4+(12–1)×-3

t12=4+11×–3

t12=4–33

t12=–29

So,12th term of A.P is –29