The first term of an ap is 5 and its 100th term is -292 find the 50th term of an Ap
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Step-by-step explanation:
a1=5
a100=-292
a100=a+(n-1) d
-292=5+(100-1)d
-292-5=99d
-297/99=d
d=-3
so,
a50=a+(n-1)d
a50=5+(49×-3)
a50=5-147=-142
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