Question

the first term of an ap is 5 the last term is 45 and the sum of its term is 1000 find the number of terms in the common difference of the AP​

Answer 1

Answer:

number of terms=40

substituting the values of a and n in a+(n-1)d, we get d.

hope it helps....

pls mark as brainliest answer

Answer 2

Answer :

no. of terms = 40

common difference = 40/39

Step-by-step explanation:

Sum of n terms of an AP is given by

S = n/2(a+l)

where S = sum of n terms

n = no. of terms

a = first term if AP

l = last term of AP

Putting given values we get

=1000 = n/2(5+45)

=1000 = n/2(50)

=20 = n/2

=40 = n

We know that nth term of an AP is given by

t = a + (n-1)d

where t is the nth term, a is first term, and d is common difference of AP

Putting given values

45 = 5 + (40-1)d

40 = 39 (d)

40/39 = d