Question

the first term of an arithmetic sequence is 1 and the sum of first 4 terms is 100 find the first 4 terms

Answer 1

Hey There!!


We are given that the first term is 1.


Let the common difference be d.

So, Terms of AP are: 1, 1+d, 1+2d, 1+3d


Now, Sum of these first four terms is 100.

So, 1+1+d+1+2d+1+3d = 100
So, 4 + 6d = 100
So, 6d = 96
So, d = 16


Thus, we have the first four terms as: 1, 17, 33, 49




Hope it helps
Purva
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