Question

The first term of an arithmetic sequence is 3 and common difference 2 a) What is the 101th term of this sequence?​

Answer 1

Answer:-

According to the Question

It is given that ,

• First term of AP ,a = 3
• Common difference ,d = 2
• Term ,n = 101

We have to calculate the 101th term of the given sequence .

As we know that the term of AP is calculated by the

• an = a + (n-1)d

where,

• n denote term
• a denote first term
• d denote common difference

Substitute the value we get

$\longrightarrow$ a₁₀₁ = 3+(101-1)2

$\longrightarrow$ a₁₀₁ = 3+(100)2

$\longrightarrow$ a₁₀₁ = 3 + 200

$\longrightarrow$ a₁₀₁ = 203

• Hence, the 101th term of given AP is 203 .

Answer 2

Given :-

The first term of an arithmetic sequence is 3 and common difference

To Find :-

101th term

Solution :-

We know that

aₙ = a + (n - 1)d

a₁₀₁ = 3 + (101 - 1) × 2

a₁₀₁ = 3 + 100 × 2

a₁₀₁ = 3 + 200

a₁₀₁ = 203

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