The first term of an arithmetic sequence is 30 and the sum of the first 4 terms is 300.find
the first 4 terms
Answers
Answered by
2
Answer:
The first term a is given by 30 , let the common difference be d
Sum of first three terms =300
Sum of n terms of an AP is given by (n÷2)×(2a+(n-1)×d)
In this case n=3 and a=30
(3÷2)×(60+2d)=300
60+2d=200
2d=140
d=70
The second term is 30+70=100
The third term is 100+70=170
Answered by
2
Answer:
mark as brainlist please it may help u
Attachments:
Similar questions