the first term of ap=6 and common difference is 5 what will be it's 11 th term
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11th term of ap will be 56
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It is given that the first term of an A.P is a=6 and the common difference is d=5.
Let us find the following terms:
a+d=6+5=11
a+2d=6+(2×5)=6+10=16
a+3d=6+(3×5)=6+15=21
We know that the general form of an arithmetic progression with first term a and common difference d is a,a+d,a+2d,......
General term=a
n
=a+(n−1)d
Hence, the required A.P is 6,11,16,21,.....
11 term of AP will be 56
its the answer...
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