Question

the first term of arithmeic sequence is 30 and the sum of firs​

Answer 1

Answer:

The first term a is given by 30 , let the common difference be d

Sum of first three terms =300

Sum of n terms of an AP is given by (n÷2)×(2a+(n-1)×d)

In this case n=3 and a=30

(3÷2)×(60+2d)=300

60+2d=200

2d=140

d=70

The second term is 30+70=100

The third term is 100+70=170