Question

the first term of sequence is 13 the term to term rule is 'take away 5' what is the 4th term

Answer 1

The 4th term is -2.

Step-by-step explanation:

Since we have given that

a = 13

d = -5

So, 4 th term would be

$a_4=a+(4-1)d\\\\a_4=a+3d\\\\a_4=13+3\times -5\\\\a_4=13-15\\\\a_4=-2$

Hence, the 4th term is -2.

# learn more:

What are the first 5 sequence of 4th term is 2 and7 th term is 3? ​

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Answer 2

Answer:

The 4th term is -2.

Step-by-step explanation:

since we have given that

since we have given thata=13

since we have given thata=13d= -5

since we have given thata=13d= -5so, 4th term would be

since we have given thata=13d= -5so, 4th term would be a4= a+ (4-1) d

since we have given thata=13d= -5so, 4th term would be a4= a+ (4-1) da4= a +3d

since we have given thata=13d= -5so, 4th term would be a4= a+ (4-1) da4= a +3da4= 13+3× -5

since we have given thata=13d= -5so, 4th term would be a4= a+ (4-1) da4= a +3da4= 13+3× -5a= 13 -15

since we have given thata=13d= -5so, 4th term would be a4= a+ (4-1) da4= a +3da4= 13+3× -5a= 13 -15a4= -2

Hance, the 4th term is -2.