The first terms of two gp are equal , 3rd term of 1st gp and 5th term of 2nd gp are equal.The ratio of 67th term of 1st gp to 133rd term of 2nd gp is ?
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Let the first term be a
common ratio be r for first gp and R for second gp
ar² = aR^4
⇒r² = R^4
⇒ (r²/R^4)= 1
and (ar^66)/(aR^132) = (r²/R^4)^33 =(1)^33 = 1
common ratio be r for first gp and R for second gp
ar² = aR^4
⇒r² = R^4
⇒ (r²/R^4)= 1
and (ar^66)/(aR^132) = (r²/R^4)^33 =(1)^33 = 1
Answered by
2
Answer:
Let the first term be a
common ratio be r for first gp and R for second gp
ar² = aR^4
⇒r² = R^4
⇒ (r²/R^4)= 1
and (ar^66)/(aR^132) = (r²/R^4)^33 =(1)^33 = 1
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