Question

the first three teams of an A. P. respectively are 3y-1, 3y+5 and 5y+1. find the value of y​

Answer 1

Answer:

Since its an AP series

So common difference is same

Therefore

$3y + 5 - 3y + 1 = 5y + 1 - 3y - 5 \\ 6 = 2y - 4 \\ 2y = 6 + 4 \\ 2y = 10 \\ y = 5$

Answer 2

Answer:

this is correct...........