Question

The first three terms of an ap are 3y â 1, 3y + 5 and 5y + 1 then y equals to

Answer 1

$\boxed{\bold{\underline{2 \: \times \: middle \: term = sum \: of \: left \: terms}}} \\ \\ \\ Hence, \\ \\ \\ 2( 3y + 5 ) = 3y + 1 + 5y + 1 \\ \\ \\ 6y + 10 = 8y + 2 \\ \\ \\ 10 - 2 = 8y - 6y \\ \\ \\ 8 = 2y \\ \\ \\ \frac{ 8}{ 2} = y \\ \\ \\ \boxed{ \bold{ y = 4 }} \\ \\ \\ \\ \underline{ So \: y \: equals \: to \: 4}$