the first three terms of an AP respectively are 3y-1, 3y+5 and 5y-1. find the value of y
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Hey buddie
This is a general equation for three terms in an AP
2 times middle term = first term + second term
2b = a+c
2(3y+5) = 3y-1+5y-1
6y+10= 8y-2
2y = 12
y = 6
Hope it helped you ;)
Have a great day
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Here.. u can go through this attachment.
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rajats965096:
bro your 1 step is wrong comman difference is 4 check it again and you will found your mistake
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