the first time, common difference and last term of an ap are 12, 6 and 252 respectively, find the sum of all terms of this A. P
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Answered by
207
a = 12
d = 6
an = 252
a+(n-1)d = 252
12 + (n-1)6 = 252
n-1 = 240/6
n = 41
Sn = n/2 [a + an]
= 41/2 (12 + 252)
= 41/2 × 264
= 41 × 132
= 5412.
HOPE THIS WILL HELP U :)
d = 6
an = 252
a+(n-1)d = 252
12 + (n-1)6 = 252
n-1 = 240/6
n = 41
Sn = n/2 [a + an]
= 41/2 (12 + 252)
= 41/2 × 264
= 41 × 132
= 5412.
HOPE THIS WILL HELP U :)
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