Question

the first two digits of a 4 - digit number is the LCM of 3 and 11. the last two digits are the square of 8. Find the square root of the 4- digit number.​

Answer 1

Step-by-step explanation:

The first 2 digits are LCM of 3 and 11

= 33

The last 2 digits are square of 8

= 64

∴ The  4 - digit no. = 3364

Now,

 Square root of 3364 = $\sqrt{3364}$

                                    = $\sqrt{ 58 X 58}$

                                    = 58          ( Ans )

HOPE THIS IS HELPFUL !!!  : )