Question

The first two terms of a geometric sequence are a1 = 1/3 and a2 = 1/6. What is a8, the eighth term? A. 1/256 B. 1/384 C. 1/128 D. 1/768

Answer 1

a2/a1=(1/6)/(1/3)=1/2
a8 = 1/3×(1/2)^7
=0.0026041667
=1/384
a8=1/384
ans:B.1/384
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Answer 2

Given First term a1 = (1/3), Second term a2 = (1/6).

We know that common ratio r = (a2/a1)

= > (1/6) * (3/1)

= > (1/2).

Now,

We know that nth term an = a * r^(n - 1).

Given 8th term, So,

= > a8 = (1/3) * (1/2)^(8 - 1)

= > (1/3) * (1/2)^7

= > (1/3) * (1/128)

= > (1/384).

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