Question

the floor of a building consists of 3000 tiles which a rhombus shaped diagonals of each of the tiles are 45 cm and 30 cm find the total cost of polishing the floor if cost per metre square is 25 rupees

Answer 1

we have

total number of tiles = 3000

area of 1 tile =1/2×d1×d2

=1/2×45×30

=675

therefore area of 3000 tiles = 675×3000

=2025000

total cost =2025000×25

=50625000 rupees

Answer 2

Answer:

Rs. 5062.5

Step-by-step explanation:

The shape of each tile is a rhombus,

Therefore, the area of a rhombus can be calculated by using the formula:

=(d1*d2)/2

substituting the values,

=(45cm*30cm)/2

=(0.45m*0.30m)/2

=0.0675 square meters.

Number of tiles=3000

Thus, the area of 3000 tiles=0.0675*3000

                                              =202.5 square meters.

Cost for polishing 1 square meter=25 Rs.

Cost for polishing 202.5 square meters=202.5*25

                                                                 =5062.5 Rs.