the floor of a building consists of 3000 tiles which are Rhombus shaped the diagonals of each of the tiles are 45 cm and 30 cm find the total cost of polishing the floor if cost per metre square is rupees 2.50
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hiii friend
here is your answer
area of one tile =multiplication of diogonals
=45×30
=1350cm^
so the area of floor=3000×1350
=4050000cm^2
area in meter =405m^2
as the of polishing area of one m^2 is rs.2.50
so cost of polishing 405m^2=405×2.5
=rs1012.5
glad to help you
hope it helps
thank you.
here is your answer
area of one tile =multiplication of diogonals
=45×30
=1350cm^
so the area of floor=3000×1350
=4050000cm^2
area in meter =405m^2
as the of polishing area of one m^2 is rs.2.50
so cost of polishing 405m^2=405×2.5
=rs1012.5
glad to help you
hope it helps
thank you.
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