the floor of a building consists of 3000 tiles which are rhombus shaped and each of diagonal is 45 cm and 30 cm in length . Find the cost of polishing the floor if the cost per sq . m is Rs 4
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Area of rhombus =(Product of its diagonals)
Area of each tile

= 675 cm2
Area of 3000 tiles = (675 × 3000) cm2 = 2025000 cm2 = 202.5 m2
The cost of polishing is Rs 4 per m2.
Cost of polishing 202.5 m2 area = Rs (4 × 202.5) = Rs 810
Thus, the cost of polishing the floor is Rs 810.
Area of each tile

= 675 cm2
Area of 3000 tiles = (675 × 3000) cm2 = 2025000 cm2 = 202.5 m2
The cost of polishing is Rs 4 per m2.
Cost of polishing 202.5 m2 area = Rs (4 × 202.5) = Rs 810
Thus, the cost of polishing the floor is Rs 810.
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