The floor of a building consists of 3000 tiles which are rectangular shaped and each of its side is 25cm and 20cm in length. Find the total cost of polishing the floor, if the cost per m2 is Rs 4.
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1
Answer:
Rs. 600
Step-by-step explanation:
Area of 1 tile = Length × breadth
= 25 × 20 = 500 cm^2 = 0.05 m^2
Now as floor consists of 3000 tiles and area of 1 tile is 0.05 m^2,
Total area of the floor = 0.05 × 3000 = 150 m^2
Now, cost of polishing 1 m^2 floor = Rs. 4 (given)
Total cost of polishing 150 m^2 floor
= 150×4
= Rs. 600
Answered by
1
First, we will find out the area of each tile
Area of each tile = 20 × 25
= 500 cm²
Now, we are given that there are 3000 tiles
So, total area = 500 × 3000
= 1500000 cm²
1 cm² = 10⁻⁴ m²
Therefore, 1500000 cm² = 150 m²
Now, it is given that the cost of polishing per m² is Rs. 4
So, total cost = 150 × 4
= 600
So, the total cost of polishing will be Rs. 600
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