Question

The floor of a building consists of around 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of flooring if each tile costs rupees 20 per m².

Answer 1

Answer: Rs 4050

Step-by-step explanation: area of each tile= 1/2x45x30 sq cm

now @Rs 20/1sq m= Rs 20/10000 per sq cm Therefore total cost= 3000x Rs 20/10000x 1/2x 45x30 = Rs 4050

Answer 2

Answer:

Step-by-step explanation:

Diagonal 1 = d1= 45cm  ( Given)

Diagonal 2 = d2= 30cm   ( Given)

Number of tiles= 3000   ( Given)

Rate per m²= 20   ( Given)

Area of Rhombus= 1/2×d1×d2

= (1/2) × 45 × 30 =675

Area of 1 tile= 675 cm² = 675/10000 m²

Area of 3000 tiles= 3000 × (675/10000) as [1cm²= 1/10000m²]

Cost of Polishing the floor = Total Area × rate

= (3000 × 675 × 20)/10000

= 3× 675× 20/10

= 3× 67.5× 20

=  4050

Thus, the total cost of polishing the floor is Rs 4050.