Question

the floor of a building consists of around 3000 tiles which are rhombus shaped and each of its diagonals are 45cm and 30cm in length. Find the total cost of flooring if each tile costs rupees 20 per 2

Answer 1

45*30\2=675
675*3000*20=40500000rs/2=20250000.

Answer 2

ANSWER:-

The tiles used on floor are in rhombus shape.

The diagonals of each tile,d1= 45 cm

d2= 30 cm

Area of each tile=1/2d1d2

=1/2×45×30

=675 cm2

Number of tiles on the floor=3000

Total area of the floor=No.of tiles×Area of each tile

=3000×675=2025000cm2

1cm2 =1/10000 m2

Area =2025000/10000 m2

=202.5m2

Cost of flooring each tile per m2 = Rs.20

Total cost of flooring=202.5×20

=Rs.4050