Question

the floor of a building constants of 3000 tiles which are Rhombus shaped and each of its diagonals are 45 cm and 30 cm in length find the total cost of polishing the floor if the cost per metre² is rs 5​

Answer 1

Answer:

Given,

Total number of tiles used = 3000

since tile is in the shape of rhombus

and diagonals are 45 cm and 30 cm

thus, d1 = 30 cm

d2 = 45 cm

Area of one tile = Area of rhombus

=1/2×d1×d2

=1/2×30×45

=15×45

=675cm²

Area of 3000 tiles= 3000× Area of one tile

= 3000×675

=2025000cm²

Now, we need to find cost

since cost is given per m²

we need to convert the area into m²

Area = 2025000cm²

= 2025000×(1/100)²m²

=2025000/10000 m²

=202.5m²

Now

Cost of polishing 1 m²= 5

cost of publishing 202.5 m² = 5×202.5

= 5×2025/10

=5×405/2

=1012.5

Hope it helps.

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