Math, asked by sanjeevs1940, 1 year ago

The floor of a hall is 20m long and 15m wide find the number of tiles required to cover the floor if the dimension of one tile is 20m multiply 10m


lovendsken: i hope tile is in cm

Answers

Answered by lovendsken
5

Answer:

150 titles

Step-by-step explanation:

area of floor is 20 × 15 = 300m ×100 = 30000cm

area o tile is 20 × 10 = 200cm

area of n tiles is n×200= 30000

no of tiles is 150

Answered by Anonymous
0

\tt ฏGIVEN:−

\tt length \: of \: floor = 4m =400cm

\tt breadth\: of \: floor= 3m = 300cm

\tt length\: of \: single \: tile= 8cm

\tt breadth\: of \: single \: tile= 6cm

\tt ฏFIND:-

\tt no. \: of \: tiles \: reqire = ?

\tt ฏSOLUTION:-

\tt area \: of \: floor = 400 \times 30 \\ \tt = 120000 {cm}^{2}

\tt area \: of \: each \: tile= 8 \times 6 = 4 {cm}^{2}

\tt now \: let \: no. \: of \: tiles = x

\tt = > area \: of \:hall= x\times area \: of \: each

\tt = > 120000 = x(48)

\tt = > x = \frac{ \cancel{ 120000}}{ \cancel{48}} = 2500

\boxed{ \tt so \: total \: no. \: of \: tile \: is \boxed{2500}}

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