the floor of a rectangular hall has a perimeter 250 m if the cost of painting the four walls at the rate 10 per metre square is Rs 1500 find the height of the hall
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Given perimeter of the rectangular floor = 250 m
Hence 2(l + b) = 250
Therefore, (l + b) = 125 --- (1)
Area of four walls, A = 15000/10 = 1500 sq m
That is 2h(l + b) = 1500
2h x 125 = 1500
h = 1500/250 = 6
Thus the height of the hall is 6 m
Hence 2(l + b) = 250
Therefore, (l + b) = 125 --- (1)
Area of four walls, A = 15000/10 = 1500 sq m
That is 2h(l + b) = 1500
2h x 125 = 1500
h = 1500/250 = 6
Thus the height of the hall is 6 m
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Step-by-step explanation:
Let length, breadth, and height of the rectangular hall be l, b, and h respectively.
Area of four walls = 2lh+2bh
= 2(l+b)h
Perimeter of the floor of hall = 2(l+b)
= 250 m
Area of four walls = 2(l+b) h = 250h m2
Cost of painting per square meter area = Rs.10
Cost of painting 250h square meter area = Rs (250h×10) = Rs.2500h
However, it is given that the cost of paining the walls is Rs. 15000.
15000 = 2500h
Or h = 6
Therefore, the height of the hall is 6 m.
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