Question

The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four
walls at the rate of 10 per metre sq.is 15000. find the height of the hall
(Hint: Area of the four walls - Lateral surface area)​

Answer 1

a

aStep-by-step explanation:

aStep-by-step explanation:Given:

aStep-by-step explanation:Given:Perimeter=250m

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h=250h m

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h=250h m⇒Cost of painting per m

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h=250h m⇒Cost of painting per m area = Rs. 10

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h=250h m⇒Cost of painting per m area = Rs. 10⇒Cost of painting 250h m

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h=250h m⇒Cost of painting per m area = Rs. 10⇒Cost of painting 250h m area = Rs(250h×10)

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h=250h m⇒Cost of painting per m area = Rs. 10⇒Cost of painting 250h m area = Rs(250h×10)= Rs.2500h

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h=250h m⇒Cost of painting per m area = Rs. 10⇒Cost of painting 250h m area = Rs(250h×10)= Rs.2500h⇒Painting cost of walls = Rs. 15000

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h=250h m⇒Cost of painting per m area = Rs. 10⇒Cost of painting 250h m area = Rs(250h×10)= Rs.2500h⇒Painting cost of walls = Rs. 15000⇒2500h=15000

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h=250h m⇒Cost of painting per m area = Rs. 10⇒Cost of painting 250h m area = Rs(250h×10)= Rs.2500h⇒Painting cost of walls = Rs. 15000⇒2500h=15000⇒h= 2500/15000

aStep-by-step explanation:Given:Perimeter=250m⇒Area of 4 walls =2lh+2bh=2(b+l)h⇒Perimeter of floor of wall =2l+2b⇒2(l+b)=250 m∴ Area of 4 walls =2(l+b)h=250h m⇒Cost of painting per m area = Rs. 10⇒Cost of painting 250h m area = Rs(250h×10)= Rs.2500h⇒Painting cost of walls = Rs. 15000⇒2500h=15000⇒h= 2500/15000⇒h=6m

Answer 2

Step-by-step explanation:

Let length, breadth, and height of the rectangular hall be l, b, and h respectively.

Area of four walls = 2lh+2bh

= 2(l+b)h

Perimeter of the floor of hall = 2(l+b)

= 250 m

Area of four walls = 2(l+b) h = 250h m2

Cost of painting per square meter area = Rs.10

Cost of painting 250h square meter area = Rs (250h×10) = Rs.2500h

However, it is given that the cost of paining the walls is Rs. 15000.

15000 = 2500h

Or h = 6

Therefore, the height of the hall is 6 m.