The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four
walls at the rate of 10 per m’ is 15000, find the height of the hall.
[Hint: Area of the four walls = Lateral surface area.]
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Given :
- Perimeter of the floor of a rectangular hall = 250 m
- Cost of painting the four walls at the rate of 10 per m² = Rs. 15000
To find :
- Height of the hall
Knowledge required :-
→ Formula of area of four walls :-
- Area of four walls = 2(l + b)h
→ Formula of perimeter of rectangle :-
- Perimeter = 2(l + b)
where,
- l = length
- b = breadth
Solution :
Perimeter of the floor = 2(l + b) = 250 m
Area of four walls = 2(l + b)h = (250)h = 250h m²
Area of four walls = 250h m²
Cost of painting 1 m² of the wall = Rs. 10
Cost of painting 250h m² of the wall = 10 × 250h = Rs. 2500h
But, cost of painting the four walls = Rs. 15000
So,
⠀⠀⠀⇒ 15000 = 2500h
⠀⠀⠀⇒ 15000/2500 = h
⠀⠀⠀⇒ 150/25 = h
⠀⠀⠀⇒ 6 = h
★ Therefore, height of the hall = 6 m
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