Question

The floor of a rectangular hall has a perimeter 250m. If the cost of painting the four walls at the rate of rs 10 per m2 is rs 1500 . Find the hieght of the hall

Answer 1

Hlo friend..

Here is ur answer :

Perimeter of Rectangular hall = 250 m
$2(l + b) = 250$

Cost of painting the four walls at the rate of rs 10 per m2 is rs 15000.

CSA of Rectangular hall =
$\frac{15000}{10} = 1500$

CSA Of Rectangular hall = 1500 m

$2(l + b)h = 1500$

Let the height be h.

$250h = 1500$

$h = \frac{1500}{250}$


$h = 6$


Height = 6m

HOPE IT HELPS YOU..

REGARDS
@sunita

Answer 2

Heya,

Given:-
Perimeter = 250m
Cost of painting the four walls = Rs.10/m^2 = Rs.1500

To Find:-
Height of the hall

Solution:-
Perimeter = 2 (l + b)
250 = 2 (l + b)
250/2 = l + b
125 = l + b

Cost = Rs.10/m^2 = Rs.1500

CSA of the hall = 1500/10
CSA of the hall = 150

To find height,

CSA of the hall = 2h (l + b)
150 = 2h (150)
150 = 250h
150/250 = h
0.6m = h

Hope my answer helps you :)

Regards,
Shobana