Math, asked by TheRedMonsTer, 10 months ago

the floor of a rectangular hall has a perimeter of cost 250m. its height is 6cm find the cost of painting its 4 wall at the rate of 6₹ sq.m​

Answers

Answered by sp6559568
12

\bf\large{\underline{Question:-}}

the floor of a rectangular hall has a perimeter of cost 250m. its height is 6cm find the cost of painting its 4 wall at the rate of 6₹ sq.m

\bf\large{\underline{Given :-}}

  • perimeter = 250 sq.m
  • height=6cmm
  • cost of painting of 4 wall at the rate of 6₹

\bf\large{\underline{To\:find:-}}

  • cost of painting = ?

\bf\large{\underline{Solution:-}}

\bf→ Perimeter\:of\:floor = 250m\\\bf→ 2(l+b)=250\\\bf→ height = 6cm

Lateral surface area = 2(l+b)×h

→ 250×6

→ 1500\bf m^2

\bf→ 1m^2\:rate\:of\: painting=6 Rs.\\\bf→ 1500×6 = 9000 Rs.

Hence,

the cost of painting of its 4 wall is 9000 .Rs

Answered by Anonymous
23

\bf\large{\underline{Question:-}}

the floor of a rectangular hall has a perimeter of cost 250m. its height is 6cm find the cost of painting its 4 wall at the rate of 6₹ sq.m

\bf\large{\underline{Given :-}}

  • perimeter = 250 sq.m
  • height=6cmm
  • cost of painting of 4 wall at the rate of 6₹

\bf\large{\underline{To\:find:-}}

  • cost of painting = ?

\bf\large{\underline{Solution:-}}

\tt→ Perimeter\:of\:floor = 250m\\\tt→ 2(l+b)=250\\\tt→ height = 6cm

Lateral surface area = 2(l+b)×h

→ 250×6

→ 1500\bf m^2

\tt→ 1m^2\:rate\:of\: painting=6 Rs.\\\tt→ 1500×6 = 9000 Rs.

Hence,

the cost of painting of its 4 wall is = 9000 .Rs

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