Question

the floor of a rectangular room has length 4 metre and breadth 3.2 metre find the number of tiles required to cover the floor if each side of tiles measures 40 cm​

Answer 1

Given:

• The length of the rectangular field is 4 m
• The breadth of the rectangular field is 3.2 m
• And the side of the square tile is 40 cm

To find:

The number of tiles required to cover the rectangular room

Now,

Area of the rectangular room

= l*b

= 4*3.2

= 12.8m²

We aknow that

1 m = 100 cm

1 m² = 10000 cm²

So,

Converting the area of the rectangular field from m sq. to cm sq.

= 12.8 m² = 128000 cm²

• Side of one tile is 40 cm

Area of one tile

= (side)²

= (40)²

= 1600 cm²

Now

Number of tiles required to cover the rectangular room is

= (Area of the rectangular room)/(Area of one tile)

= 128000/1600

= 80 number of tiles.

Hence,

80 numbers of tiles are required to cover the rectangular room.

Answer 2

Given:

• The length of floor= 4m = 400cm
• The breadth of floor = 3.2 m = 320cm
• Length of tile = 40cm

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Need to find :

• Number of tiles=?

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Solution:

Area if rectangular tile = length × breadth

⟹Area= 400cm × 320cm

⟹$\bold{\purple{Area= 128000 {cm}^{2}}}$

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Area of rectangular tile= Number of square tile× Its area

and

Area of a square = side× side

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Area of rectangular tile= Number of square tile× Its area

⟹ 128000 = n× 40× 40

⟹ n= 128000 ÷ 1600

⟹ n= 80

Therefore, $\bold{\red{\large{\boxed{80\: Tiles}}}}$ will be required.