Question

The floor of a room is 10m 20cm long and 6m 60cm broad. Find the minimum number of square tiles of same size needed to pave the entire floor.

Answer 1

Step-by-step explanation:

Length of the floor =8 m 96 cm=896 cm

Breadth of the floor =6 m 72 cm=672 cm

H.C.F. of 896 and 672 is =2×2×2×2×2×7=224

So, the required size of the square tile must be 224×224

Hence, the minimum number of square tiles of the same size needed to cover the floor =

Area of one square tile

Area of the floor

=

(224×224)

(896×672)

=

50176

602112

=12

Hence, 12 square tiles each of 224 cm×224 cm will be needed to cover the entire floor.

please change the number according

Answer 2

Answer:

Answer:187

Answer:187Step-by-step explanation:

Length of the floor =10 m 20cm=1020 cm

Breadth of the floor =6m 60 cm=660 cm

H.C.F. of 1020 and 660 is = 2 × 2 × 3 × 5 ×5

So, the required size of the square tile must be 60×60

Hence, the minimum number of square tiles of the same size needed to cover the floor = (Area of one square tile/Area of the floor)

(1020 × 660) / (60 × 60)=

673200/3600

=187/1

=187 is your final answer

Hence, 187 square tiles each of 60 cm×60 cm will be needed to cover the entire floor.