Question

The floor of a room is 10m 25cm long and 8m 75cm broad. Find the least number of square tiles of the same size for covering the whole floor.

Answer 1

Answer:

• length = 10m25cm or =10.25m
• Breadth= 8m75cm or= 8.75m

Now area = l × B

$area = 10.25 \times 8.75m ^{2}$

$area = 89.6875 \: m^{2}$

A/Q ,The least number of square tiles for covering the floor is given by

$\frac{area \: of \: floor}{common \: size \: of \: tiles}$

let common size of tiles be x

So the leasten number of tiles would requires is

$\frac{89.6875}{x} \: no.$