Question

The floor of a room is 6 m long and 4.2 m wide. It has a border of 20 cm laid with
green marble. The remaining floor has a white marble. Find the area covered with green
and white marbles separately.
m ontructed in the middle of a garden crossing each other​

Answer 1

Answer:

Step-by-step explanation:

The area of the white marble 23.2 m²

The area of the green marble 2m²

Given data :

Length of the given room = 6 metres = 600 centimetres [Term of unit conversion is 1 metre = 100 centimetres]

Width of the given room = 4.2 metres = 420 centimetres [Term of unit conversion is 1 metre = 100 centimetres]

Width of the green marble border = 20 centimetres

• The total length and breadth of the floor includes both the green and white marble.

• So, room's length = white marble length + green marble width

Room's width = white marble width + green marble width

• Now,the white marble's length = Room's length - Green marble's width = 600-20 = 580 centimetres

• Now,the white marble's width

= Room's width - Green marble's width = 420-20 = 400 centimetres

• So,the white marble's area = (580cm ×400cm) = 5.8 m × 4m = 23.2 m² (answer)

• Room's area = green marble's area + white marble's area = 6 m × 4.2 m = 25.2m²

• Green marble's area = Room's area - White marble's area = 25.2-23.2 = 2 m² (answer)

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