The floor of a room is 8 m 96 cm long and 8 m 72 cm broad . Find the minimum number of square tiles of the same size needed to covered the entire floor
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Answered by
11
Answer:
Step-by-step explanation:
8 m 96 cm = 896 cm
8m 72 cm = 872 cm
Now largest possible tile will be HCF of 896 and 872
HCF(896,872) = 8
No of such tiles required = Area of room ÷ area of tiles
896×872 ÷ 8× 8 = 12,208 tiles
Answered by
1
Answer:
=184
Step-by-step explanation:
so, first we will add the numbers that is 8+96
and 8+72
=104+80
=184
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