Question

the floor of a room is 8cm 50cm long ad 7m 25cm wide. find the largest size of each tile and hence find the least number of tiles requried



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Answer 1

Answer:

Length of the floor =8 m 96 cm=896 cm

Breadth of the floor =6 m 72 cm=672 cm

H.C.F. of 896 and 672 is =2×2×2×2×2×7=224

So, the required size of the square tile must be 224×224

Hence, the minimum number of square tiles of the same size needed to cover the floor =

Area of one square tile

Area of the floor

=

(224×224)

(896×672)

=

50176

602112

=12

Hence, 12 square tiles each of 224 cm×224 cm will be needed to cover the entire floor.

Step-by-step explanation:

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