Question

the zeroes of the polynomial 3x2+15x+12​

Answer 1

Answer:

3x^2+12x+3x+12

(3x^2+12x)+(3x+12)

3x(x+4)+3(x+4)

(x+4)(3x+3)

x= -4,-1

Answer 2

Given :

The polynomial equation 3x² + 15x + 12

To find:

The zeroes of the polynomial

Calculation:

By factorization method

=> 3x² + 15x + 12

=> 3x² + 12x + 3x + 12

=> 3x(x+4) + 3(x+4)

=> (3x+3)(x+4) = 0

=> 3x+3=0  ,  x+4 = 0

=> x=-1, x=-4

The zeroes of the polynomial 3x² + 15x + 12 are -1, -4