the zeroes of the polynomial 3x2+15x+12
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Answered by
1
Answer:
3x^2+12x+3x+12
(3x^2+12x)+(3x+12)
3x(x+4)+3(x+4)
(x+4)(3x+3)
x= -4,-1
Answered by
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Given :
The polynomial equation 3x² + 15x + 12
To find:
The zeroes of the polynomial
Calculation:
By factorization method
=> 3x² + 15x + 12
=> 3x² + 12x + 3x + 12
=> 3x(x+4) + 3(x+4)
=> (3x+3)(x+4) = 0
=> 3x+3=0 , x+4 = 0
=> x=-1, x=-4
The zeroes of the polynomial 3x² + 15x + 12 are -1, -4
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