Question

The floor of a room is in the shape of a square of side 4.8 meters. The floor is to be covered with tiles of perimeter 1.2 meters. Find the cost of covering the floor if each tile cost $48

Answer 1

Answer:

$12288

Step-by-step explanation:

=> Side of a square shaped room = S=4.8 m

=> Area of square shaped room = A = Side²=4.8² = 23.04 m²

=> Permite of a tile= 4a = 1.2

=> Side of a tile= a = 1.2/4= 0.3 m

=> Area of a tile = @= a²=0.3² = 0.09m²

=> Number of tiles used be N { Let}

Now

=> N ×@=A

=> N × 0.09 = 23.04

=> N= 23.04/0.09= 256

So number of tiles used = 256

=> Cost of each tile = $48



=> Cost of covering floor = N × cost of covering each tile

=> Cost of covering floor = 256×48 =$12288

Answer 2

here is your answer :

» $ 12288

→ side of square shaped room - s = 4.8 m

→ Area of square shaped room - a = 4.8 ² = 23.04 m²

→ Perimeter of tile - 1.2 m

→ side of tile - 1.2 / 4 = 0.3 m

→ Area of tile - € = a² = 0.3 m = 0.9 m²

» Let the number of tiles be used T

» T × € = A

» T × 0.09 = 23.04

» T = 23.04 / 0.09 = 256

› Number of tiles used = 256

› cost of tiles = $ 48

› cost of covering floor = T × cost of covering tiles

» 256 × 48 = $ 12288

#Be brainly