the floor of a room is in the shape of the square of side 4.8 M the floor is to be covered with square tiles of a parameter 1.2 M find the cost of covering the floor if each tile cost rupees 27
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(4.8cm)²= area of floor
=23.04cm²
perimeter of tile = 1.2m
side of tile=1.2/4=0.3m
Area of tile=0.09m
no of tiles=23.04/0.09=256 tiles
cost of covering = 256 X 27=Rs6912
=23.04cm²
perimeter of tile = 1.2m
side of tile=1.2/4=0.3m
Area of tile=0.09m
no of tiles=23.04/0.09=256 tiles
cost of covering = 256 X 27=Rs6912
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