The floor of a room of size 7cm *4m is to be covered by rectangular tiles of size 60cm by 50cm.find(i) the number of tiles required to cover the floor of the room and (it) the total cost if one dozen tiles cost Rs 300
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hi!!!
here's ur answer...
given the length and breadth of the rectangular floor is 7cm and 4cm.
area of the rectangular floor = l × b
= 7 × 4
= 28m²
length and breadth of the rectangular tiles is 60cm = 0.6m and 50cm = 0.5m
area of the rectangular tile = l × b
= 0.6 × 0.5
= 0.3m²
1. hence the number of tiles required to cover the floor = 28/0.3
= 93.3333...
hence, 93 tiles are required (approx.)
ATQ, the cost of 1 dozen (12) tiles is rs 300
therefore cost of one tile = 300/12
= rs 25
hence, total cost = 25 × 93 = rs 2325
hope this helps..!!
here's ur answer...
given the length and breadth of the rectangular floor is 7cm and 4cm.
area of the rectangular floor = l × b
= 7 × 4
= 28m²
length and breadth of the rectangular tiles is 60cm = 0.6m and 50cm = 0.5m
area of the rectangular tile = l × b
= 0.6 × 0.5
= 0.3m²
1. hence the number of tiles required to cover the floor = 28/0.3
= 93.3333...
hence, 93 tiles are required (approx.)
ATQ, the cost of 1 dozen (12) tiles is rs 300
therefore cost of one tile = 300/12
= rs 25
hence, total cost = 25 × 93 = rs 2325
hope this helps..!!
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