The floor of an Auditorium is covered by 6 carpets two carpets have dimension 12 metre into 8 m two 6 metre into 4 m and the remaining two 4 m into 3 M what is the area of the Auditorium floor
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dimension of first two carpets = 12m × 8m
area of first two carpets together = 2× 12 × 8 = 192m^2
dimensions of second two carpets= 6m * 4m
area of second two carpets together= 2× 6 × 4 = 48m^2
dimensions of third two carpets= 4m * 3m
area of third two carpets together = 2×4×3=24m^2
area of all carpets together = 192 + 48 + 24 = 264m^2 = area of auditorium
area of first two carpets together = 2× 12 × 8 = 192m^2
dimensions of second two carpets= 6m * 4m
area of second two carpets together= 2× 6 × 4 = 48m^2
dimensions of third two carpets= 4m * 3m
area of third two carpets together = 2×4×3=24m^2
area of all carpets together = 192 + 48 + 24 = 264m^2 = area of auditorium
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the answer is 264 sq. m ans
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