Question

The floor of building consist of around 6000 tiles which are rhombus shaped and each of its diagonal are 45cm and 30cm in length . Find the cost of flooring if each tile costs rupees 20 per m ​

Answer 1

ABCD be a tile,

such that BD = 45cm & AC = 30cm

Area of each tile = AC×BD/2

• =45×30/2
• =675cm^2

Area of 6000 tiles = 6000×675

• 4050000 cm^2
• = 405 m^2

Cost of flooring = Rs (405*20)

• = Rs.8100

Answer 2

Answer:

Rs 810

Step-by-step explanation:

Solution: Length of one diagonal, d1 = 45 cm and d2= 30 cm

Area of one tile = 1/2 d1 d2

= ½ x 45 x 30 = 675

Area of one tile is 675 cm^2

Area of 3000 tiles is

= 675 3000 = 2025000 cm^2

=2025000/ 10000

= 202.50 m^2

Cost of polishing the floor per sq. meter = 4

Cost of polishing the floor per 202.50 sq. meter = 4 x 202.50 = 810

Hence the total cost of polishing the floor is Rs. 810.