the floor of rectangular hall has perimeter 250 m it's hieght is 5m find the cost of painting it's four walls (including doors , window , etc ) at the rate of ₹8 per sq m
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Answered by
0
Answer:
The answer is 1250m²
Step-by-step explanation:
Perimeter= 250m
:. 2(l+b) =250m
l+b= 250/2
l+b= 125m
Height= 5m
C.S.A. of Room(4 walls)
= 2(hl + hb)
= 2h (l+b)
= 2x5 (125)
= 10(125)
=1250m²
Answered by
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Total Cost [C]
Given:
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- Perimeter of the hall = 250 m
- Height of the hall = 5 m
To find:
- Cost of painting the four walls at the rate of ₹8 per m² .
Solution:
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- Area of the four walls = Perimeter of the floor × Height
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We know perimeter of Rectangle → 2(l + b)
Therefore, substituting the values in it, we get
2( l + b ) h
250 × 5
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1250 m²
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From the given cost of painting of 1 square metre was ₹8 then cost of painting of the four walls is
= Total area × Cost
1250 × 8
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= ₹ 10,000
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As per the Question the cost of painting of the four walls is ₹ 10,000.
₹ 10,000.⠀⠀⠀⠀⠀⠀⠀⠀
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