Question

The floor of the rectangular hall has perimeter 400cm. Let the cost of painting of four walls at the rate of Rs.12 per cm squares Rs. 24,000, then find the height of the hall.

Answer 1

Perimeter of rect = 400 cm

2(l+b) = 400

l+b = 400/2 = 200 cm

Curved surface area of cuboid = 2h(l+b)

= 2h(200)

= 400h

Cost of painting per cm² = 12 Rs

1 cm² = 12 Rs

Cost of painting 4 walls of cuboid = 24000 Rs

CSA × rate per cm² = 24000

400h × 12 = 24000

h = 24000/(12×400)

h = 5 cm

I think 5 cm and 400 cm sum is too less for a rectangular hall

It should be in metres

If it is in metres, change all my units to metres

Hope it helps

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Answer 2

primeter of rectangle =2(l+b)
400=2(l+b)
400/2 =l+b
200 = l+b
C.S.A = 24000/12
C.S.A =2000
C.S.A =2(l+b)h
2000= 2(200)h
2000/400 = h
5 = h
h= 5