The floor of the room of a building is 80 m long and 50 m wide. The room is surrounded by a verandah which is 5m wide and is covered by tiles of dimensions 40 cm x 40 cm
1)What is the total area of the floor including verandah?
Please tell with explanation
Answers
Answer:
ANSWER IS RS.5400
Step-by-step explanation:
Given, Length of room =4.5m and breadth of room =4 m
So, Area of room =4.5×4=18 m
2
Area of room =18×(10000 cm
2
)=180000cm
2
Size of tiles =(15 cm×10 cm)
So, Area of tile one =15×10=150 cm
2
So, number of tiles required to cover the floor=
Area of one tile
Area of floor
=
150
180000
=1200
It is given that for one tile it costs Rs. 4.50
Therefore. cost of covering the floor with tiles
=4.50×1200=Rs.5400
Given:
- Length and Breadth of the floor (PQRS) is 80 m and 50 m respectively.
- The room is surrounded by a verandah which is 5 m wide.
To Find:
- Total area of the floor including verandah (ABCD) = ??
Process:
To find the area of the floor including verandah we first have to find the length and breadth of the floor including verandah. To find that we have to add 10 m to the length and breadth of the room, as the room is surrounded by the verandah with a width of 5 m and adding both the sides (5 m + 5 m) it becomes 10 m. So, length will be (80 + 10)m = 90 m; and breadth will be (50 + 10)m = 60 m. After, that we can find the area of the floor including verandah by using the formula: Area of rectangle = (L × B) sq. units.
Formula Used:
Where,
L = Length
B = Breadth
Solution:
Length of the floor (PQRS)= 80 m
Breadth of the floor (PQRS) = 50 m
∵ Width of the verandah = 5 m
∴ Length of the floor including verandah (ABCD) = (80 + 10)m
= 90m
Breadth of the floor including verandah (ABCD) = (50 + 10)m
= 60m
Area of the floor including verandah = (L × B) sq. units
= (90 × 60)m²
= 5400m²
Hence, area of the floor including verandah is 5400m².