Math, asked by bhagyalakshmich27, 3 months ago

The flour in a bag is divided into three portions according to the
4:6:9. If the smallest portion is 28 kg, how much is the biggest
(A) 54 (B) 63
(C) 72 (D) 98

Answers

Answered by hritikagrahari79
2

Answer:

63 kg

Step-by-step explanation:

28÷4 = 7

= 9×7 = 63

63 is the answer of the question

Answered by lightingisbeautiful
0

Answer: 63

explaining:

The flour in a bag is divided into three parts = 4:6:9

given smallest portion is 28kg

so, highest ratio number is = 9

portion = 28÷4 = 7kg

biggest portion = 7kg×9 = 63

Similar questions