Question

The flux entering and leaving a closed surface are 5*
105 and 4x 105 SI unit respectively then the net charge
inside the surface will be
__7
(
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Answer 1

Answer:

-77+(-78) +94+8+(-37) +(-75)

Explanation:

Here is your answer

Answer 2

The net charge inside the surface will be -8.85 × $10^{-7} C$

Explanation:

Given:

• The flux entering the closed surface is $5$×$10^{5}$
• The flux leaving the surface is $4$ × $10^{5}$

To find: The net charge inside the surface

Formula used: Gauss law ϕ = Q/ϵ0

Gauss law:

"The total flux associated with a closed surface equals 1/ε0 times the charge encompassed by the closed surface, according to the Gauss law "

ϕ = Q/ϵ0

A closed surface's total charge is proportional to the total flux encompassed by the surface.

Q is total electric charge encompassed by the surface

ϕ is total flux

ϵ0 is electric constant.

Фin = $5$ × $10^{5}$ mks unit

Фout = $4$× $10^{5}$ mks unit

Ф = Фout - Фin

Ф=( 4 - 5) $10^{5}$ mks unit

Ф = -1 $10^{5}$ mks unit

Apply gauss law

Ф = Q/ϵ0

Q = ϵ0 × Ф

Q = (-1 × $10^{5}$ mks unit)/8.85 ×$10^{-12} C$

Q = -8.85 × $10^{-7} C$

Final answer:

The net charge inside the surface will be -8.85 × $10^{-7} C$

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