Physics, asked by gummudumounika, 3 months ago

the focal length of a convex mirror is 10 cm. if an object of height 2 cm is placed at a distance of 20 cm from the mirror then the height of the image is​

Answers

Answered by MystícPhoeníx
67

Answer:

  • Height of Image is 6 cm.

Explanation:

Given:-

  • Focal Length ,f = 10 cm
  • Object height ,ho = 2 cm
  • Object distance ,u = -20 cm

To Find:-

  • Image Height ,hi

Solution:-

Firstly we calculate the image position . Using Mirror Formula

• 1/v + 1/u = 1/f

where,

  • v is the Image Position
  • u is the object distance
  • f is the focal length

Substitute the value we get

→ 1/v = 1/f - 1/u

→ 1/v = 1/10 - 1/(-20)

→ 1/v = 1/10 + 1/20

→ 1/v = 2+1/20

→ 1/v = 3/20

→ v = 20/3 cm

  • Hence, the image position is 20/3 cm behind the mirror.

Now, using Magnification Formula

m = hi/ho = -v/u

substitute the value we get

→ hi/2 = -20/3/(-20)

→ hi/2 = 20/3/20

→ hi/2 = 3

→ hi = 6 cm

  • Hence, the height of image is 6 cm.

Hαrsh: Nice Answer bruh❤
Anonymous: Great ! Bro .
Answered by Anonymous
48

Answer:

Given :-

  • Focal length = 10 cm
  • Height of object = 2 cm
  • Object Distance = -20 cm

To Find :-

Height of mirror

Solution :-

As we know that

1/v + 1/u = 1/f

1/v = 1/10 - 1/-20

1/v = 1/10 + 1/20

1/v = 2+1/20

1/v = 3/20

v = 20/3

Now,

hi/ho = -v/u

hi/2 = -20/3/-20

hi/2 = 3

hi = 3 × 2

hi = 6 cm

HENCE :-

Height of image is 6 cm.

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