Physics, asked by AnkitaGupta10th, 1 year ago

The focal length of objective lens and eye piece of an astronomical telescope are 130cm and 5cm respectively .Find the magnifying power of the telescope for relaxed eye and length of telescope .

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Answered by pankajbenwal2014

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Related questions The magnifying power of telescope is 9. when it is adjusted for parallel rays, the distance between objective and eye piece is found to be 20 cm. The focal length of lenses are
answered Jan 23, 2014 by meena.p magnification m = 9
m = fo
fe
9 = f0
fe
f0 = 9f e
f0 + f e = 20
10 f e = 20
fe = 2
f0 = 2 ×9
= 18 c

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AnkitaGupta10th: i want

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pankajbenwal2014: then

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sreekar8: just wantedly i kept

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